Area of the Longest Diagonal

Easy

You are given a list of rectangles rects, where rects[i] = [length, width]. Find the rectangle whose diagonal is the longest and return its area. If several rectangles share the longest diagonal, return the largest area among them.

Example 1

rects=[[2, 9], [6, 7]] → 42

The squared diagonals are 4 + 81 = 85 and 36 + 49 = 85, a tie. Of the areas 18 and 42 we take the larger.

Example 2

rects=[[10, 1], [7, 7]] → 10

The first rectangle has the longer diagonal (√101 vs √98), so the answer is its area, 10.

Example 3

rects=[[4, 4]] → 16

Constraints

1 ≤ len(rects) ≤ 100
len(rects[i]) == 2
1 ≤ rects[i][0], rects[i][1] ≤ 100

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Topics

Array

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Input

rects=[[2, 9], [6, 7]]

Expected

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