Flip the Characters in Place

Easy

You are given a list of characters chars. Put its elements in reverse order: the first character must end up last, the second one second to last, and so on. Return the flipped chars. Try to use only O(1) extra memory.

Example 1

chars=['r', 'a', 'd', 'a', 'r', 's'] → ['s', 'r', 'a', 'd', 'a', 'r']

After the flip the list is ['s', 'r', 'a', 'd', 'a', 'r'].

Example 2

chars=['Q', '?'] → ['?', 'Q']

The two characters just swap: ['?', 'Q'].

Example 3

chars=['z'] → ['z']

A single character has nowhere to go, so the list stays the same.

Constraints

1 ≤ chars.length ≤ 10⁵
each chars[i] is a printable ASCII character

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Topics

Two Pointers String

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Input

chars=['r', 'a', 'd', 'a', 'r', 's']

Expected

['s', 'r', 'a', 'd', 'a', 'r']

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